arc length? SOS
arc length? SOS
Is there a way to specify the length of an arc?
Re: arc length? SOS
I'd like to know this too !!!
All I've done before is :
From the known radius, calculate the included angle of the segment of a circle that will contain the required length of arc. Then draw that segment of the circle using the calculated angle.
Peter
All I've done before is :
From the known radius, calculate the included angle of the segment of a circle that will contain the required length of arc. Then draw that segment of the circle using the calculated angle.
Peter
Re: arc length? SOS
Its late here... could you rework the classic circumference formula?
fat guy in a little coat
Re: arc length? SOS
Circumference of a circle = πd or ( 3.14159 x the diameter)
So if you want to find the included angle of the segment req'd to draw an arc of a certain length then this angle is found by :
•Calculate the total circumference of the circle from the known diameter (d) ( or 2x radius )
•Divide the result by the known arc length req'd
•Divide the result into 360º
e.g to draw an arc that is req'd to be 7.5" long with a radius of 5" ( 10" diam )
• circumf = 10" (d) x 3.14159 .............................= 31.4159
• 31.14159 divided by the req'd arc length of 7.5".......= 4.18879
• 360º divided by 4.18879 ..................................= 85.943669º ( angle of segment )
So .... start to draw the arc of 5" radius, set 'A' to 4.18879 and complete the arc of 7.5" length.
Peter
So if you want to find the included angle of the segment req'd to draw an arc of a certain length then this angle is found by :
•Calculate the total circumference of the circle from the known diameter (d) ( or 2x radius )
•Divide the result by the known arc length req'd
•Divide the result into 360º
e.g to draw an arc that is req'd to be 7.5" long with a radius of 5" ( 10" diam )
• circumf = 10" (d) x 3.14159 .............................= 31.4159
• 31.14159 divided by the req'd arc length of 7.5".......= 4.18879
• 360º divided by 4.18879 ..................................= 85.943669º ( angle of segment )
So .... start to draw the arc of 5" radius, set 'A' to 4.18879 and complete the arc of 7.5" length.
Peter
Re: arc length? SOS
Oops ! Sorry ......... Set 'A' to 85.943669º ( not 4.18879 )
Peter
Peter
Re: arc length? SOS
I love geometry, I really do, but when I am DRAFTING, I would rather just be able to specify my desired length - either during the operation or in the Object Info palette...peatle wrote:Circumference of a circle = πd or ( 3.14159 x the diameter)
So if you want to find the included angle of the segment req'd to draw an arc of a certain length then this angle is found by :
•Calculate the total circumference of the circle from the known diameter (d) ( or 2x radius )
•Divide the result by the known arc length req'd
•Divide the result into 360º
e.g to draw an arc that is req'd to be 7.5" long with a radius of 5" ( 10" diam )
• circumf = 10" (d) x 3.14159 .............................= 31.4159
• 31.14159 divided by the req'd arc length of 7.5".......= 4.18879
• 360º divided by 4.18879 ..................................= 85.943669º ( angle of segment )
So .... start to draw the arc of 5" radius, set 'A' to 4.18879 and complete the arc of 7.5" length.
Peter
Re: arc length? SOS
Me too ........ !